Skip an Index in JavaScript Array map()
JavaScript's map() function always executes over every value.
That means you can't skip an index.
map() will always include exactly one value in the result array for every value in the original array.
However, there a couple of alternatives to work around this issue.
filter()
You can use JavaScript's filter() function before you map() to remove the values you don't want to map.
const array = [1, 2, 3, 4, 5];
// Return an array with all the values multiplied by 2, but exclude
// any values that are >= 4.
const filteredArray = array.filter(item => item < 4);
array.map(entry => entry * 2); // [2, 4, 6]flatMap()
You can use JavaScript's flatMap() function instead of map().
The flatMap() function "flattens" the return value from the callback for each value.
If your callback returns an empty array [], flatMap() will not add any values to the resulting array.
const array = [1, 2, 3, 4, 5];
// Return an array with all the values multiplied by 2, but exclude
// any values that are >= 4.
const newArray = array.flatMap(item => item < 4 ? [item * 2] : []);
console.log(newArray); // [2, 4, 6]
spread in combination with ternary
If you're constructing an array using the spread operator ..., you can conditionally avoid adding elements to the array by using the spread operator combined with the ternary operator.
const array = ['a'];
let check = true;
const newArray = [
...array,
// Only add 'b' and 'c' to the array if `check` is truthy
...(check ? ['b', 'c'] : [])
];
newArray; // ['a', 'b', 'c']